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2y^2-8y-120=0
a = 2; b = -8; c = -120;
Δ = b2-4ac
Δ = -82-4·2·(-120)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-32}{2*2}=\frac{-24}{4} =-6 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+32}{2*2}=\frac{40}{4} =10 $
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